Answer to Question #231548 in Quantum Mechanics for hanata yuji

Question

A photon of wavelength 4 angstrom an electron at rest and this photon is deflected at an angle of 1500 to its original direction. Determine the wavelength of this photon after the collision

Answer 1

The wavelength of scattered photon is

$\lambda =\lambda _0+(\frac{h}{mv})(1-cos150^o)$

$=(4\times 10^{-10})+ \frac{(6.626\times 10^{-34})}{(9.11\times 10^{-31}(3\times 10^8)}(1-cos150^o)$

$=4.0452\times 10^{-10} m= 4.0452 Angstrom$