Question #231562

calculate the de Broglie wavelength of a free electron with an energy of 50 GeV

Expert's answer

The de Broglie wavelength of this electron is


λ=hc2Em0c2=2.48⋅10−17 m.\lambda=\frac{hc}{\sqrt{2Em_0c^2}}=2.48·10^{-17}\text{ m}.

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