Question #108337

Write an expression for semi-empirical formula for binding energy of nuclei given
by Weizsacker and discuss its each term. Using this formula, calculate the binding
energy per nucleon for
235 U.

Expert's answer

The semi-empirical formula for binding energy of nuclei given by Weizsacker is written below:


BE=avAasA2/3acZ(Z1)A1/3aa(NZ)2A+ap1A1/2,B_E=a_vA-a_sA^{2/3}-a_c\frac{Z(Z-1)}{A^{1/3}}-a_a\frac{(N-Z)^2}{A}+a_p\frac{1}{A^{1/2}},

where

av=15.8 MeVas=18.3 MeVac=0.71 MeVaa=23.2 MeVap=±11.2 MeVa_v=15.8\text{ MeV}\\ a_s=18.3\text{ MeV}\\ a_c=0.71\text{ MeV}\\ a_a=23.2\text{ MeV}\\ a_p=\pm11.2\text{ MeV}\\

are best-fit parameters.,

AA - nucleon number, NN - neutron number, ZZ - proton number.

The first term with subscript v is volume term.

The second term with subscript s is surface term.

The third term with subscript c is coulomb term.

The fourth term with subscript a is asymmetry term.

The fifth term with subscript p is pairing term - defines the effect of spin-coupling. It's positive with Z, N, A even, zero with A odd, negative with Z, N odd and A even.

Therefore, for 235U this will give


BE=1796.1 MeV.B_E=1796.1\text{ MeV}.

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