The low of Plank
ϵ(ν,T)=c22hν3⋅ekThν−11.
dνdϵ(ν,T)=0
So, we get that
−kThν⋅ekThν−1ekThν+3=0 → (x−3)ex+3=0 (x=kThν)
From this equation x=2.821439372122
ν=hxkT=6.62⋅10−342.821439372122⋅1.38⋅10−23⋅1000≈58.8⋅1012Hz=58.8THz
Infrared radiation (IR).
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