The absolute value of electric force between proton and electron in the hydrogen atom is "F_E = \\frac{k e^2}{R^2}", where "k = 9 \\cdot 10^9 N m^2 C^{-2}" is Coulomb constant, "e = 1.6 \\cdot 10^{-19} C" is the charge of the electron, "R" is the radius of the hydrogen atom.
The absolute value of the gravitational force between proton and electron in the hydrogen atom is "F_G = \\frac{G m_e m_p}{R^2}", where "G = 6.67 \\cdot 10^{-11} m^3 kg^{-1}s^{-2}" is the gravitational constant, "m_e = 9.11 \\cdot 10^{-31} kg" is the mass of the electron, "m_p = 1.67 \\cdot 10^{-27} kg" is the mass of the proton.
The ratio of "F_E" to "F_G" is "\\frac{k e^2}{R^2} \\frac{R^2}{G m_e m_p} = \\frac{k e^2}{G m_e m_p}".
Calculating with the values above, obtain "\\frac{F_E}{F_G} \\approx 2.2 \\cdot 10^{39}".
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