Answer to Question #99897 in Physics for Kelvin

Question

Deter the current that will be drawn from a 6v source connected to a 60mm length of wire, with a resistvity of0. 0185micro ohm meter. With area of wire given as 0.001meter square

Answer 1

The resistance:

$$R=\rho\frac{l}{A}$$

The current:

$$I=\frac{U}{R}=\frac{AU}{\rho l}$$

$$I=\frac{(0.001)6}{(0.0185\cdot 10^{-6})(0.06)}=5.4\cdot 10^{6}\ A$$