A flight range of a body thrown at the angle "\\alpha" to the horizontal with a velocity "v" is "L=\\frac{v^2\\sin 2\\alpha}{g}". It follows from this formula that if two angles "\\alpha" and "\\beta" are complementary (i.e. "\\alpha+\\beta=\\frac{\\pi}{2}") then flight ranges would be equal if initial velocities are equal.
In the case concerned a ball was thrown at two complementary angles and the flight ranges were different. So it can be explained as that initial velocities were different.
Comments
Leave a comment