Answer to Question #84364 in Physics for bien soriano

Question

A Carnot cycle heat engine operates between 172 K and 335 K. B Its efficiency is?

Answer 1

We can find the efficiency of the Carnot heat engine from the formula:

$$\eta = (1 - \frac{T_C}{T_H})\cdot 100\%,$$

here,

$$T_C$$

is the absolute temperature of the cold reservoir,

$$T_H$$

is the absolute temperature of the hot reservoir.

Then, we get:

$$\eta = (1 - \frac{T_C}{T_H})\cdot 100\% = (1 - \frac{172 K}{335 K})\cdot 100\% = 48.6\%.$$

Answer:

$$\eta = 48.6\%$$

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