1. Calculate the distance of separation between 2 electron (in a vacuum) for which the electric force between them is equal to the gravitation on one of them at the earth surface. Take the mass of the electron =9.1*10-³¹ kg, Charge of electron = 1.6*10-19 C
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Expert's answer
2019-01-21T11:10:09-0500
The balance of forces condition
F_gravity=F_electric
So
mg=k q^2/r^2
The distance
r=√((kq^2)/mg)=√((9×〖10〗^9×(1.6×〖10〗^(-19) )^2)/(9.1×〖10〗^- ³¹×9.8))=5.1 m
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