Question #71547

F1=150N F2=80N F3=110N F4=100N

Find the dot product 150N•80N and 110N•100N using magnitudes
Find the dot product 150N•110N and 80N•100N using components
Find the cross product 150N x 80N and 110N x 100N using magnitudes
Find the cross product 150N x 100N and 80N x 110N using components
1

Expert's answer

2017-12-05T12:57:07-0500

Answer on Question #71547-Physics-Other

F1=150N F2=80N F3=110N F4=100N


Solution

Find the dot product 150N•80N and 110N•100N using magnitudes


(150)(80) cos(9030+20)=2084(150)(80)\ \cos(90 - 30 + 20) = 2084(110)(100) cos(9015)=2847(110)(100)\ \cos(90 - 15) = 2847


Find the dot product 150N•110N and 80N•100N using components


150 cos30 (80 sin20)+150 sin30 (80 cos20)=2084150\ \cos 30\ (-80\ \sin 20) + 150\ \sin 30\ (80\ \cos 20) = 2084100 cos15 (0)100 sin15 (110)=2847100\ \cos 15\ (0) - 100\ \sin 15\ (-110) = 2847


Find the cross product 150N x 80N and 110N x 100N using magnitudes


(150)(80) sin(9030+20)=11818(150)(80)\ \sin(90 - 30 + 20) = 11818(110)(100) sin(9015)=10625(110)(100)\ \sin(90 - 15) = 10625


Find the cross product 150N x 100N and 80N x 110N using components


150 cos30150 sin3080 sin2080 cos20=150 cos30 (80 cos20)150 sin30 (80 sin20)=11818\left| \begin{array}{cc} 150\ \cos 30 & 150\ \sin 30 \\ -80\ \sin 20 & 80\ \cos 20 \end{array} \right| = 150\ \cos 30\ (80\ \cos 20) - 150\ \sin 30\ (-80\ \sin 20) = 118180110100 cos15100 sin15=100 sin15 (0)100 cos15 (110)=10625\left| \begin{array}{cc} 0 & -110 \\ 100\ \cos 15 & -100\ \sin 15 \end{array} \right| = -100\ \sin 15\ (0) - 100\ \cos 15\ (-110) = 10625


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