Answer on Question #71527-Physics-Other
The position of a particular moving in a straight line is given by x=3+4t+3t2. Where x is in the meter and time is in second find the values of the following physical quantities for the particular at t=2s:
1) Position
2) Displacement
3) Velocity
4) Acceleration
Solution
1.
x(2)=3+4(2)+3(2)2=23m.
2.
d=x(2)−x(0)=23−3=20m.
3.
v=4+6tv(2)=4+6(2)=16sm.
4.
a=3s2m.
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