Answer to Question #335387 in Physics for mae

Question

1. A capacitor consists of two square metal plates, each measuring 5.0 x 10-2 m on a side. In between the plates is a sheet of mica measuring 1.0 x 10-4 m thick. (a) What is the capacitance of this capacitor? (b) If the charge in one plate is 2.0 x 10-8 C, what is the potential difference between the plates?

Answer 1

(a)

$$C=\frac{\kappa \epsilon_0A}{d}\\ =\frac{5.4*8.85*10^{-12}*5.0*10^{-2}}{1.0*10^{-4}}=2.4*10^{-8}\:\rm F$$

(b)

$$V=\frac{q}{C}=\frac{2.0*10^{-8}}{2.4*10^{-8}}=0.83\:\rm V$$