Answer to Question #334981 in Physics for Venus L.

Question #334981

A electron passes through a magnetic field at 60° to the field at a velocity of 3.5×10⁶m/s. What is the magnitude of the force acting on the electron having a 0.45T magnetic field?

Expert's answer

F=qvB\sin\theta\\ =1.6*10^{-19}*3.5*10^6*0.45*\sin 60^\circ\\ =2.2*10^{-13}\:\rm N

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