Answer to Question #334782 in Physics for Jhonard

Question #334782

A long solenoid has 500 turns. When a current of 2 A is passed through it, the

resulting magnetic flux linked with each turn of the solenoid is 4×10

−3 Wb. find

self-inductance.

Expert's answer

"\\phi=NLI"

"L=\\frac{\\phi}{IN}=\\frac{4*10^{-3}}{2*500}=4*10^{-6}\\:\\rm H"

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