Answer to Question #269984 in Physics for Carry Bee

Question

Leonard wanted to measure the depth of the dried-up well beside their house. He dropped a coin in to it, and it took 2 seconds for the coin to reach the ground. What is the total depth of the well? (Disregard the external factors that might affect the coin’s velocity.)

Answer 1

The depth is

$$h=gt^2/2=9.8·2^2/2=19.6\text{ m}.$$