Answer to Question #269935 in Physics for Rusy

Question

A wheel rotatung at 1p.5rads-1 takes 5.2 to stop calculate

Angular acceleration

The number if revolution the wheel makes before it stops

Answer 1

The angular acceleration:

$$\alpha=\omega/t=1.5/5.2=0.29\text{ rad/s}^2.$$

The number of revolutions:

$$\phi=\alpha t^2/2=3.92\text{ rad}.$$