Question #261500

Archaeologists found an old campfire site. Carbonated firewood was found in the excavation, the ratio of carbon-14 and carbon-12 isotopes of which had decreased from the corresponding sample of fresh firewood to 13.2%. How old was the campfire site?




Expert's answer

N(t)=N0e−ln⁡2⋅t/T1/2N(t)=N_0e^{-\ln2\cdot t/T_{1/2}}


For carbon-14 T1/2=5730  yearsT_{1/2}=5730 \ \ years


0.132N0=N0e−ln⁡2⋅t/T1/2→0.132=e−0.69t/(5730⋅365⋅24⋅3600)→0.132N_0=N_0e^{-\ln2\cdot t/T_{1/2}}\to 0.132=e^{-0.69t/(5730\cdot365\cdot24\cdot3600)}\to


t=16739  yearst=16739\ \ years . Answer




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