Answer to Question #260416 in Physics for Boss

Question #260416

At what temperature will the molecule of an ideal gas have twice the the rms speed they have at 20°c

1
Expert's answer
2021-11-03T10:19:58-0400

The speed is proportional to the square root of temperature:


vrms=3RTM, u=2vrms=23RTM=3R(4T)M,v_\text{rms}=\sqrt\frac{3RT}{M},\\\space\\ u=2v_\text{rms}=2\sqrt\frac{3RT}{M}=\sqrt\frac{3R(4T)}{M},

so, the temperature is 4T=4(273+20)=1172 K or 899°C.


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