Let's first find the acceleration of the block:
Fh−Ffr=ma,Fh−μsW=gWa,a=gWFh−μsW,a=32.17 s2ft100 lb40 lb−0.25×100 lb=4.82 s2ft,a=4.82 s2ft×1 ft0.3048 m=1.47 s2m.Finally, we can find the velocity of the block at the end of 3s from the kinematic equation:
v=v0+at=0+1.47 s2m×3 s=4.41 sm.
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