Question #260200

You and your friend ride the merry-go-round at an amusement park. You ride at the outermost horse, with a radius of 3m, while your friend rides on a seat closer to the center of the ride, with a radius of 2m. The ride lasts for 6 revolutions, lasting a total of 3 minutes.


Do you and your friend experience the same centripetal acceleration? Prove by calculating the centripetal acceleration for both you and your friend


1
Expert's answer
2021-11-04T18:07:11-0400

(a) Let's first find the period of the merry-go-round ride:


T=TimeNumber of revolutions=3 min×60 s1 min6 rev=30 s.T=\dfrac{Time}{Number\ of\ revolutions}=\dfrac{3\ min\times\dfrac{60\ s}{1\ min}}{6\ rev}=30\ s.

(b) The centripetal acceleration is not the same for the persons that ride on a seats located at different radii from the center of the ride. The person that rides on a seat located farther from the center of the ride experiences larger centripetal acceleration. Let's prove that by calculations:


ac1=v2r=4π2r1T2=4π2×2 m(30 s)2=0.088 ms2,a_{c1}=\dfrac{v^2}{r}=\dfrac{4\pi^2r_1}{T^2}=\dfrac{4\pi^2\times2\ m}{(30\ s)^2}=0.088\ \dfrac{m}{s^2},ac2=v2r2=4π2r2T2=4π2×3 m(30 s)2=0.132 ms2,a_{c2}=\dfrac{v^2}{r_2}=\dfrac{4\pi^2r_2}{T^2}=\dfrac{4\pi^2\times3\ m}{(30\ s)^2}=0.132\ \dfrac{m}{s^2},ac2>ac1.a_{c2}>a_{c1}.

As we can see from the calculations, the person that rides on a seat located farther from the center of the ride experiences larger centripetal acceleration.


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