Question

A parkour artist jumps from one rooftop to another. He jumps off the first rooftop with a velocity of 5m/s, angled at 30° to the horizontal. He stays airborne for 0.70 seconds before landing on the second rooftop.

What was the vertical velocity (𝑣⃗2𝑦) of the parkour artist when they reached the second rooftop?

Answer 1

The time during which the body reached its maximum height

$t=v\sin30°/g=5\cdot\sin30°/9.81=0.255\ (s)$

$t_1=0.7-0.255=0.445\ (s)$

The vertical velocity

$v_y=gt=9.8\cdot0.445=4.37\ (m/s)$