Answer to Question #259798 in Physics for Precious

Question #259798

A particle accelerate uniformly from a speed of 10m/s to 20m/s in 5 seconds.if it maintain this speed for 5 seconds before being brought to rest in another 5 seconds, calculate the total distance

1
Expert's answer
2021-11-01T19:24:58-0400

Using the kinematic formulas, find the distance travelled during the first part:


d1=10m/s+20m/s25s=75md_1 = \dfrac{10m/s + 20m/s}{2}\cdot 5s = 75m

During the second part:


d2=20m/s5s=100md_2 = 20m/s\cdot 5s = 100m

And the third part:


d3=0m/s+20m/s5s=4md_3 = \dfrac{0m/s + 20m/s}{5s} = 4m

The total distance is:


d=75m+100m+4m=179md = 75m + 100m + 4m = 179m

Answer. 179 m.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment