Answer to Question #259798 in Physics for Precious

Question

A particle accelerate uniformly from a speed of 10m/s to 20m/s in 5 seconds.if it maintain this speed for 5 seconds before being brought to rest in another 5 seconds, calculate the total distance

Answer 1

Using the kinematic formulas, find the distance travelled during the first part:

$$d_1 = \dfrac{10m/s + 20m/s}{2}\cdot 5s = 75m$$

During the second part:

$$d_2 = 20m/s\cdot 5s = 100m$$

And the third part:

$$d_3 = \dfrac{0m/s + 20m/s}{5s} = 4m$$

The total distance is:

$$d = 75m + 100m + 4m = 179m$$

Answer. 179 m.