Question #259678

Given a body, of negligible weight, initially a point (20,30) in the SI convention on the x-y plane, is fired at 400m/s at an angle of 60degrees(to the vertical). What coordinates will the body assume after 30sec of travel

1
Expert's answer
2021-11-01T12:53:04-0400

The horizontal and vertical components of velocity:


vx=vsinθ,vy=vcosθ.v_x=v\sin\theta,\\ v_y=v\cos\theta.

The x-coordinate after 30 s:


x=x0+vxt=x0+vtsinθ=10412 m.x=x_0+v_xt=x_0+vt\sin\theta=10412\text{ m}.


The y-coordinate:


y=y0+vytgt22=y0+vtcosθgt22=1620 m.y=y_0+v_yt-\frac{gt^2}2=y_0+vt\cos\theta-\frac{gt^2}2=1620\text{ m}.


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