Question #259644

a rubber ball of 20 g is attached to a string of 0.8 cm length if the ball is swung in a horizontal circle making 1 revolution in 0.9 seconds find the speed of the ball and the centripetal acceleration and centripetal Force


1
Expert's answer
2021-11-01T12:53:11-0400

The speed:


v=2πrT=2π0.008m0.9s=0.056 m/s.v=\frac{2\pi r}{T}=\frac{2\pi·0.008\text m }{0.9\text s}=0.056\text{ m/s}.


The centripetal acceleration:


ac=v2r=0.39 m/s2.a_c=\frac{v^2}r=0.39\text{ m/s}^2.


The centripetal force:


Fc=mac=7.8103 N.F_c=ma_c=7.8·10^{-3}\text{ N}.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

Stephanie
02.11.21, 21:03

Thanks a lot it was very helpful!!!

LATEST TUTORIALS
APPROVED BY CLIENTS