Question #252443
if sound travels from air to another medium and number of oscillations decrease to fifth for the same distance in air:
-If sound takes 1/3 seconds to move 100 meter in air, find time of the same distance in another medium
- if speed of sound in air equal 300m/sec, find time of sound in the second medium for distance equal 500 meter.
1
Expert's answer
2021-10-18T11:09:38-0400

The phrase "number of oscillations decreases to fifth for the same distance in air" means that the number of complete wavelengths in the medium is 5 times smaller than in air.

For air and another medium, we have


λa=5λ.\lambda_a=5\lambda.


Find the speed of sound in air:


va=100/(1/3)=300 m/s.v_a=100/(1/3)=300\text{ m/s.}

Frequency is the same in both media. The 1/3 s in air can be represented as


ta=d/va=d/(λaf).t_a=d/v_a=d/(\lambda_a f).

The time for the 100 m in the medium can be written as


t=d/v=d/(λf)=5d/(λaf)=5ta=5/3 s.t=d/v=d/(\lambda f)=5d/(\lambda_a f)=5t_a=5/3\text{ s}.

The time for sound to cover 500 m is, therefore, 5 times longer: 25/3 s.


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