Question

For Nickel, the number density is 8×10^23 atoms/cm^3 and the electronic configuration is 1s^2 2s^2 2p^6 3s^2 3p^6 3d^8 4s^2. The value of saturation magnetisation of Nickel in its ferromagnetic states is : (use μB= 9.21×10^−21 Am^2)

Answer 1

Determine the saturation magnetization:

$$M_s=0.6μ_BN,\\ M_s=0.6(9.21·10^{−21} )(8·10^{ 29} )= 4.42⋅10 ^9 \text{ A/m.}$$