Question #251659

An airplane is in level flight at a velocity of 300 miles per hour and an altitude of 5000ft when I drops a bomb. (a) how long does the bomb take to reach the ground? (b) what will the bomb's velocity be on impact?


Expert's answer

(a) The time is


t=2h/g=25000/32=17.7 s.t=\sqrt{2h/g}=\sqrt{2·5000/32}=17.7\text{ s}.

(b) The horizontal component of velocity does not change (if we ignore air resistance) and it is 440 ft/s. The vertical component:


vy=2gh=566 ft/s, v=vx2+vy2=717 ft/s, or 488 mph.v_y=\sqrt{2gh}=566\text{ ft/s},\\\space\\ v=\sqrt{v_x^2+v_y^2}=717\text{ ft/s, or 488 mph.}


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