Answer to Question #251653 in Physics for John

Question

A stone is thrown from a sling at a speed of 40m/s at an angle of 50 °. Find (a) time of ascent; (b) maximum height reached; (c) range.

Answer 1

(a) The time of ascent is

$$t=v\sin\theta/g=3.13\text{ s}.$$

(b) Maximum height reached:

$$H=(v\sin\theta)^2/2g=47.9\text{ m}.$$

(c) Range:

$$R=v^2\sin(2\theta)/g=161\text{ m}.$$