Question

For Nickel, the number density is 8×10^23 atoms/cm^3 and the electronic configuration is 1s^2 2s^2 2p^6 3s^2 3p^6 3d^8 4s^2. The value of saturation magnetisation of Nickel in its ferromagnetic states is : (use μB= 9.21×10^−21 Am^2)

3.87×10^8A/m

4.97×10^8A/m

4.87×10^9A/m

3.97×10^9A/m

Answer 1

The saturation magnetization is

$$M_s=0.6\mu_BN=0.6(9.21×10^{−21})(8×10^{29})=\\=4.42·10^9\text{ A/m}.$$