Answer to Question #247227 in Physics for jessica

Question #247227

We’ll start with the same time data as above, but this time, you will create the position data. In the original set of data, the object increased its distance by 20 metres every 10 seconds. In this case, the object will need to cover greater and greater amounts of distance in each 10-second interval.


Time (t) in s Position (\vec{d}) in m [S]

0 0

10  

20  

30  

40  

50  

60  

70  

Now, graph your data. Compare what you see in your graph with the graph of uniform motion earlier in this activity.


Create a reflection, and record your answers to the following questions:


How does the shape of your non-uniform motion graph differ from the uniform motion graph?

What do you think the position-time graph of an object that was slowing down might look like?


1
Expert's answer
2021-10-07T08:49:05-0400


As we see, the uniform motion is represented by a straight line while the accelerated motion (orange) is represented by a parabolic curve. Comparing the distance covered during equal intervals of time, we notice that accelerated motion provides a greater position change during the same time.

The position-time graph of a slowing object would also look parabolic but it would be more and more flat as the time increases unlike the orange curve.


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