Answer to Question #247213 in Physics for Max

Question

A galvanometer of internal resistance 100Ω gives a full scale deflection for a current of 10 mA. Calculate the values of the resistance necessary to convert the galvanometer to an ammeter reading up to 10 A

Answer 1

Given:

$R_0=100\:\Omega$

$I_0=10\:\rm mA=0.01\: A$

$I=10\:\rm A$

The resistance of the shunt is given by

$$R=\frac{I_0}{I-I_0}R_0=\frac{0.01}{10-0.01}*100=0.1\:\Omega$$