Question

A galvanometer of internal resistance 100Ω gives a full scale deflection for a current of 10 mA. Calculate the values of the resistance necessary to convert the galvanometer to a voltmeter reading up to 5 V

Answer 1

The value of the shunt resistance is

$$R=\frac V{I_g}-R_g=\frac{5}{0.01}-100=400\Omega.$$