A turtle crawls along a straight line, which we will call the š„-axis with a positive direction to the right. The equation for the turtleās position as a function of time is š„(š”) = 50.0šš + (12.00šš/š 2 )š”. (a) Find the turtleās initial velocity, initial position, and initial acceleration. (b) At what time š” is the velocity of the turtle zero?
Given:
"x(t)=50.0+12.00t^2\\:\\rm (cm)"
The turtleās velocity
"v(t)=x'(t)=24.00t\\:\\rm cm\/s"The turtleās acceleration
"a(t)=v'(t)=24.00\\:\\rm cm\/s^2"
(a) The turtleās
initial velocity:
"v(0)=0\\:\\rm cm\/s"Ā initial position:
"x(0)=50.0+12.00*0^2=50\\:\\rm cm"initial acceleration:
"a(0)=24.00\\:\\rm cm\/s^2"
(b) The velocity of the turtle is zero at the instant
"t=0\\:\\rm s"
Comments
Leave a comment