Question #242536

A turtle crawls along a straight line, which we will call the 𝑥-axis with a positive direction to the right. The equation for the turtle’s position as a function of time is 𝑥(𝑡) = 50.0𝑐𝑚 + (12.00𝑐𝑚/𝑠 2 )𝑡. (a) Find the turtle’s initial velocity, initial position, and initial acceleration. (b) At what time 𝑡 is the velocity of the turtle zero?


1
Expert's answer
2021-09-26T18:47:10-0400

Given:

x(t)=50.0+12.00t2(cm)x(t)=50.0+12.00t^2\:\rm (cm)


The turtle’s velocity

v(t)=x(t)=24.00tcm/sv(t)=x'(t)=24.00t\:\rm cm/s


The turtle’s acceleration

a(t)=v(t)=24.00cm/s2a(t)=v'(t)=24.00\:\rm cm/s^2

(a) The turtle’s

initial velocity:

v(0)=0cm/sv(0)=0\:\rm cm/s

 initial position:

x(0)=50.0+12.0002=50cmx(0)=50.0+12.00*0^2=50\:\rm cm

initial acceleration:

a(0)=24.00cm/s2a(0)=24.00\:\rm cm/s^2


(b) The velocity of the turtle is zero at the instant

t=0st=0\:\rm s


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