Answer to Question #242531 in Physics for Ems

Question

Projectile Motion: Other applications


A boy throws a rock with speed y = 18.3 m/s at an angle of ∅ = 57.0

Answer 1

The range of the rock is

$$R=\frac{v^2\sin[2\alpha]}{g}=\frac{18.3^2\sin[2·57°]}{9.8}=31.2\text m.$$