Question

john throws the ball straight upward and after 1 second it reaches its maximum height then it does free fall motion which takes 2 seconds. What is its maximum height of the ball?

Answer 1

The ball falls from the highest point of its trajectory within 2 seconds:

$$h=\frac{gt^2}{2}=\frac{9.8·2^2}{2}=19.6\text{ m}.$$