Answer to Question #241986 in Physics for Kristine

Question #241986

A remote-controlled car is moving in a vacant parking lot. The velocity of the car as a function of time is given by 𝑣 = [5.00π‘š/𝑠 βˆ’ (0.0180π‘š/ 𝑠 3 )𝑑 2 ]𝑖̂+ [2.00 π‘šβ„π‘  + (0.550 π‘š 𝑠 2 ⁄ )𝑑]𝑗. (a) What are Μ‚ π‘Žπ‘₯(𝑑) and π‘Žπ‘¦(𝑑), the π‘₯- and 𝑦-components of the car’s velocity as functions of time? (b) What are the magnitude and direction of the car’s velocity at 𝑑 = 8.00 𝑠? (b) What are the magnitude and direction of the car’s acceleration at 𝑑 = 8.00 𝑠?


1
Expert's answer
2021-09-29T09:55:51-0400

(a) The x- and y-component of car's velocity:


"v_y=[2.00+ (0.550 )\ud835\udc61] \\text{ m\/s},\\\\\nv_x=[5.00 \u2212 (0.0180)\ud835\udc61^2 ]\\text{ m\/s}."


Find the acceleration:


"a(t)=v'(t)=[-0.036t]\\hat i+[0.55]\\hat j.\\\\\na_x(t)=-0.036t,\\\\\na_y(t)=\\text{const}\n=0.55\\text{ m\/s}^2."

(b) The magnitude:


"v=\\sqrt{(2+0.55\u00b78)^2+(5-0.018\u00b78^2)^2}=7.47\\text{m\/s},\\\\\\space\\\\\n\\theta=\\arctan\\frac{2+0.55\u00b78}{5-0.018\u00b78^2}\n=58.0\u00b0"

from +i toward +j.


"a=\\sqrt{(-0.036\u00b78)^2+(0.55)^2}=0.620\\text{ m\/s}^2.\\\\\\space\\\\\n\\phi=\\arctan\\frac{0.55}{-0.036\u00b78}=-62.4\u00b0"

from +i toward +j (or 62.4Β° from +i to +j).Β 


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