Question #241976

A boy on a bridge throws a stone horizontally with a speed of 25 𝑚/𝑠, releasing the stone from a point 19.6 𝑚 above the surface of the river. How far from a point directly below the boy will the stone strike the water? 


1
Expert's answer
2021-09-26T18:48:43-0400

The time of falling:


t=2h/g.t=\sqrt{2h/g}.

The horizontal distance:


R=vt=v2h/g=50 m.R=vt=v\sqrt{2h/g}=50\text{ m}.


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