Answer to Question #236845 in Physics for nati

Question #236845
A 6kg clay ball is directly against a perpendicular brick wall at a velocity of 22m/s and shatters in to pieces, which all fly backward. the wall exerts a force on the ball of 2640 N for 0.1s. one piece of mass 2 kg travel backward at a velocity of 10m/s and an angle 32 above the horizontal. A second piece of mass 1 kg travels at a velocity of 8m/s and an angle of 28 below the horizontal. what is the velocity of the third piece?
1
Expert's answer
2021-09-14T14:15:59-0400

Fx=2640 (N)   and   Fy=0F_x=2640\ (N)\ \ \ and \ \ \ F_y=0


So,


0=210sin32°18sin28°+3vyvy=6.84 (m/s)0=2\cdot10\cdot\sin32°-1\cdot8\cdot\sin28°+3\cdot v_y\to v_y=-6.84\ (m/s)


26400.1=(210cos32°18cos28°3vx)622vx=140 (m/s)2640\cdot0.1=(-2\cdot10\cdot\cos32°-1\cdot8\cdot\cos28°-3\cdot v_x)-6\cdot22\to v_x=140\ (m/s)


v=1402+6.842=140.2 (m/s)v=\sqrt{140^2+6.84^2}=140.2\ (m/s)


tanα=6.84/140=0.488α=2.79°\tan\alpha=6.84/140=0.488\to\alpha=2.79° (below the horizontal)






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