Question #236830

A dog's fur is combed, and the comb gains a charge of 8.0 nC. Find the electric force between the fur and comb when they are 2.0 cm apart. 



1
Expert's answer
2021-09-13T17:52:50-0400

There is no exact answer to this question. Since both dog and comb can not be considered as a point charges if they only 2cm apart.

But, we can attempt to apply Coulomb's law anyway, keeping in mind that the result will be definitely wrong.


F=kq1q2r2F = k\dfrac{q_1q_2}{r^2}

where q1=q2=8×109Cq_1 = q_2 = 8\times 10^{-9}C are the modulus of the charges on comb and fur (they are equal according to the charge conservation law), r=2cm=0.02mr = 2cm = 0.02m is the distance, and k=9×109Nm2/C2k = 9\times 10^9Nm^2/C^2 is the constant. Thus, obtain:

F=9×109(8×109)2(0.02)21.4×103NF = 9\times 10^9 \cdot \dfrac{(8\times10^{-9})^2}{(0.02)^2} \approx 1.4\times 10^{-3}N

Answer. 1.4×103N1.4\times 10^{-3}N (taking into account the initial note).


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