Answer to Question #234992 in Physics for Payton

Question

a car starting from rest moves in a straight line with a constant acceleration of 1.90m/s^2 for 13.0s, then travels at a constant velocity for another 13.0s. How far does it travel over the total 26s interval?

Answer 1

The distance traveled during the 13 s of accelerated motion:

$$d_1=\frac{at^2}{2}=160.55\text{ m}.$$

The velocity the car acquired:

$$v=at=24.7\text{ m/s}.$$

The distance traveled in the other 13 s:

$$d_2=vt=321.1\text{ m}.$$

The total distance:

$$d=d_1+d_2=481.7\text{ m}.$$