Question

A 20 liter container of nitrogen had a pressure of 3.2 atm. What volume would be

necessary to decrease the pressure to 1.0 atm?

Answer 1

$$P_1V_1=P_2V_2,$$ $$V_2=\dfrac{P_1V_1}{P_2}=\dfrac{3.2\ atm\cdot20\ L}{1.0\ atm}=64\ L.$$