Answer to Question #222082 in Physics for Mulatu Tesfaye

Question

Equation of path of projectile motion

Answer 1

The equation of path of projectile motion is a parabola and can be written as follows:

$$y=xtan\theta-\dfrac{gx^2}{2v^2cos^2\theta},$$

here, $x$ is the horizontal displacement of the projectile, $y$ is the vertical displacement of the projectile, $v$ is the velocity of the projectile, $\theta$ is the launch angle and $g$ is the acceleration due to gravity.