Question #222004

If a spring is stretched a distance of 0.24 m with a force of 18 N, what is the value of the spring constant k?


1
Expert's answer
2021-08-13T10:20:20-0400

The Hooke's law says

F=kxF=kx

Hence, the spring constant

k=Fx=18N0.24  m=75N/mk=\frac{F}{x}=\frac{18\:\rm N}{0.24\;\rm m}=75\:\rm N/m


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