Question #222005

 If the spring constant k of a pogo stick is 3100 N/m and the weight of the person on the pogo stick is 760 N, how much is the spring in the bottom of the pogo stick compressed?


1
Expert's answer
2021-08-16T08:31:58-0400

The Hooke's law says

F=kxF=kx

Hence, the compression of the spring

x=Fk=760N3100N/m=0.245mx=\frac{F}{k}=\frac{760\:\rm N}{3100\:\rm N/m}=0.245\:\rm m


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