Question #211040

An electric cable contains a single copper wire of radius 9mm. It's resistance is 5 ohms. This cable is replaced by 6 insulated copper wires, each of radius 3mm. The resultant resultance of cable will be?


1
Expert's answer
2021-07-01T13:17:48-0400

Find the length-resistivity ratio of the 9mm-cable:


R=ρLA9, ρL=RA9.R=\frac{\rho L}{A_9},\\\space\\ \rho L=RA_9.

The resistance of the new cable:


Re=ρLnA3, Re=RA9nA3=Rπr92nπr32=Rr92nr32, Re=50.009260.0032=7.5Ω.R_e=\frac{\rho L}{nA_3},\\\space\\ R_e=\frac{RA_9}{nA_3}=\frac{R\pi r_9^2}{n\pi r_3^2}=\frac{R r_9^2}{n r_3^2},\\\space\\ R_e=\frac{5·0.009^2}{6·0.003^2}=7.5\Omega.


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