Answer to Question #211037 in Physics for Festus

Question #211037

The electric field intensity at a point situated 4 meters from a point charge is 200N/C. If the distance is reduced to 2 meters, the field intensity will be?

Expert's answer

"E=k\\frac{q}{r^2}\\\\E'=200\\frac{4^2}{2^2}=800\\frac{N}{C}"

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