The heat produce when a certain mass of brass is heated from 25 ᵒC to 65 ᵒC is 465 Calories. The specific heat of is 0.090. Calculate the mass of brass to produce this requirement.
465 (cal)=1946.86 (J)465\ (cal)=1946.86\ (J)465 (cal)=1946.86 (J)
0.09 (cal/(kg⋅K))=377 (J/(kg⋅K))0.09\ (cal/(kg\cdot K))=377\ (J/(kg\cdot K))0.09 (cal/(kg⋅K))=377 (J/(kg⋅K))
Q=cmΔt→m=Q/(cΔt)=1946.86/(377⋅(65−25))=0.1291 (kg)Q=cm\Delta t\to m=Q/(c\Delta t)=1946.86/(377\cdot(65-25))=0.1291\ (kg)Q=cmΔt→m=Q/(cΔt)=1946.86/(377⋅(65−25))=0.1291 (kg) . Answer
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