A 45 grams of copper is heated from 35 ᵒC to 85 ᵒC.
How much heat is absorbed by the copper ? The specific heat of copper is 0.093.
0.093 (kcal/(kg⋅K))=389.4 (J/(kg⋅K))0.093\ (kcal/(kg\cdot K))=389.4\ (J/(kg\cdot K))0.093 (kcal/(kg⋅K))=389.4 (J/(kg⋅K))
Q=cmΔT=389.4⋅0.045⋅(85−35)=876.15 (J)Q=cm\Delta T=389.4\cdot0.045\cdot(85-35)=876.15\ (J)Q=cmΔT=389.4⋅0.045⋅(85−35)=876.15 (J)
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments