Question

A pendulum with a Bob mass of 5 kg is held stationery at a height h metres above the ground .when released it collides with a block of mass 2 kg which is stationery at point A .the Bob swings past A and comes to rest momentarily at a position 1/4h above the ground . Calculate the height h

Answer 1

$$0.5mv^2=mgh\\h=\frac{v^2}{2g}$$