Answer to Question #185833 in Physics for Yasmin

Question #185833

the pressure of the helium in the balloon is 100,000 Pa. The volume of the balloon is 0.030m ^3. Balloon is compressed at a constant temperature causing the volume to decrease to 0.025m^3. No helium leaves the balloon. Calculate the new pressure in the balloon


1
Expert's answer
2021-04-28T09:54:26-0400

Since the temperature and mass of the gas is constant during the process, and helium can be considered as ideal gas, we can apply the Boyle–Mariotte law (see https://en.wikipedia.org/wiki/Boyle%27s_law):


"P_1V_1 = P_2V_2"

where "P_1 = 100000Pa, V_1 = 0.030m^3" are the pressure and volume before the compression respectively, and "P_2, V_2 = 0.025m^3" are the pressure and volume after the compression respectively. Thus, expressing "P_2", obtain:


"P_2 = \\dfrac{P_1V_1}{V_2}\\\\\nP_2 = \\dfrac{100000Pa\\cdot 0.030m^3}{0.025m^3} = 120000Pa"

Answer. 120000 Pa.


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